Question

Listed Below are the amounts of mercury (in parts per million) found in tuna sushi sampled at different stores. The sample mean is 1.056 ppm and the sample standard deviation is 0.273 ppm. Use technology to construct a 90% confidence interval estimate of the mean amount of mercury in the population.

0.53 1.15 0.93 1.29 0.97 1.28 1.24

What is the confidence interval estimate of the mean amount of mercury in the population?

___ppm

Answer 1

Answer:

[0.86; 1.26]

Step-by-step explanation:

Hello!

The study variable is:

X: amount of mercury found in tuna fish. (ppm)

If this population is normally distributed, the statistic to use to estimate the population mean is the Students t.

The formula for the CI is:

X[bar] ± $t_{n-1; 1-\alpha /2}$*$\frac{S}{\sqrt{n} }$

The calculated interval is:

[0.86; 1.26]

With 90% confidence level you'd expect that the interval [0.86; 1.26] contains the population mean of the amount of mercury in tuna fish.

I hope it helps!