Question

A sister spins her brother in a circle of radius R at angular speed wi. Then the sister decreases her angular speed
to wi, with the same radius. How does the magnitude of the brother's centripetal acceleration change when the
sister slows down?

Answer 1

Answer:

The change in the centripetal acceleration of the brother,

                               Δa = V₂²/R - V₁²/R

Explanation:

Given data,

A sister spins her brother in a circle of radius, R

The angular velocity of the brother, ω₁ = V₁/R

The angular velocity of the brother, ω₂ = V₂/R

The centripetal acceleration is given by the relation

                                 a = V²/R

Therefore change in the centripetal acceleration of the brother,

                              Δa = V₂²/R - V₁²/R                                    

Answer 2

Answer:

Decreases by factor of 16

Explanation:

khan acadamy