Answer: Final speed of car is 9.99 ≈10m/s or 2.78 km/h
Explanation:
Initial speed V1=23.7 km/h=6.58 m/s
accelerationa=0.92 m/s²
Time: t=3.6 s
V2=?
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use equat.
a=(V2-V1)/t
from here we can find V2
a*t=V2-V1
a*t+V1=V2
V2=a*t+V1
V2=0.92m/s²*3.6+6.58m/s
V2=3.312m/s+6.68m/s
V2=9.99m/s ≈10m/s
