Answer:
Step-by-step explanation:
From the first two terms [tex]x^{3}[/tex] can be take as common.
Then in the second line [tex](x + a)[/tex] gets common from the both terms.
Then it has just break according to the formula of [tex]a^{3} + b^{3}[/tex]
[tex]x^{4} + ax^{3} + 8x + 8a = (x + a)x^{3} + 8(x + a) = (x + a)(x^{3} + 8) = (x + a)(x^{3} + 2^{3} ) = (x + a)(x + 2)(x^{2} -2x + 4)[/tex]