Question

A clear sheet of polaroid is placed on top of a similar sheet so that their polarizing axes make an angle of 30° with each other. The ratio of the intensity of emerging light to incident unpolarized light is:

Answer 1

Answer:

$\dfrac{I}{I_0}=\dfrac{3}{8}$

Explanation:

Given that

Angle ,θ = 30°

From Malus law,Intensity given as

$I=\dfrac{I_0}{2}cos^2\theta$

Io=Intensity of unpolarized light

I=Intensity of emerging light

Now by putting the value of angle

$I=\dfrac{I_0}{2}cos^2\theta$

$I=\dfrac{I_0}{2}cos^230^{\circ}$

We know that

$cos30^{\circ}=\dfrac{\sqrt{3}}{2}$

$I=\dfrac{I_0}{2}\times \dfrac{3}{4}$

$\dfrac{I}{I_0}=\dfrac{3}{8}$

Therefore ratio will be $\dfrac{3}{8}$

Answer 2

Answer:

Ratio of the intensity of emerging light$\frac{I}{I_{0}}=\frac{3}{8}$

Explanation:

Given:

Angle,$\theta=30^{\circ}$

Step 1:

According to Malus law,

Intensity,

$I=\frac{I_{0}}{2} \cos ^{2} \theta$

$l_{0} =$Intensity of unpolarized light

$l=$Intensity of emerging light

Step 2:

Put the value of angle

$I=\frac{I_{0}}{2} \cos ^{2} \theta$

$I=\frac{I_{0}}{2} \cos ^{2} 30^{\circ}$

We know,

$\cos 30^{\circ}=\frac{\sqrt{3}}{2}$

$I=\frac{I_{0}}{2} \times \frac{3}{4}$

So, the intensity of the ratio

$\frac{I}{I_{0}}=\frac{3}{8}$

Therefore, the ratio of the intensity of light is  $\frac{3}{8}$

To learn more, refer:

https://brainly.com/question/3917542