Question

the sum of two numbers is 32. the sum of 3 times the larger and 7 times the smaller is 128

Answer 1

Answer:

Smaller number = 8 (x)

Larger number = 24  (y)

Step-by-step explanation:

x+y=32

7x+3y=128

Solving by Elimination

-3x-3y= -96

7x+3y=128

4x=32

4x/4=32/4

x=8

-7x-7y= -224

7x+3y=128

-4y= -96

-4y/-4= -96/-4

y=24

Check answer

x+y=32

8+24=32

7x+3y=128

7(8)=3(24)=138

56+72=128

128=128