Answer:
1.2
Step-by-step explanation:
Given that X is Normally distributed random variable with an unknown mean μ and known standard deviation 6
Hence we can say for a sample of size 100, the sample mean will have a std deviation of = [tex]\frac{6}{\sqrt{100} } =0.6[/tex]
Since population std deviation is known we can use Z critical value for finding out the confidence interval
For 95% using (68-95-99.7 rules) we have z critical value =2
Hence margin of error =2(std error) = 1.2
Confidence interval 95%
Lower bound = Mean - margin of error = Mean -1.2
UPper bound = Mean +1.2
Hence , 95% of all of these values of x should lie within a distance of __1.2___ from μ .