Answer:
Explanation:
Given
Tom is on half way between the center and the outer rim
Mary is on the extreme outer rim
Suppose [tex]\omega [/tex] is the angular velocity of ride with radius of outer rim be R
[tex]\alpha =[/tex]angular acceleration of Ride
At any instant both Tom and Mary experience the same angular speed
(b)Linear velocity at any instant
[tex]v_{Tom}=\omega \times R[/tex]
[tex]v_{Mary}=\omeag \times \frac{R}{2}[/tex]
Thus Tom has higher linear speed
(c) For radial Acceleration
[tex]a_r=\omega ^2\times r[/tex]
[tex]a_{Tom}=\omega ^2\times R[/tex]
[tex]a_{Mary}=\omega ^2\times \frac{R}{2}[/tex]
Tom has higher radial Acceleration as it is directly Proportional of radius