Answer:
2- propanol treated with metal base NaH followed by hydrogen bromide to form 2- propoxypropane.
Explanation:
Formation of secondary halide:
Firstly propene reacts with sulfuric acid or water to form 2- Propanol.
Formation of primary halide:
Also, according to the Anti markovinikov rule propene undergoes addition to the hydrogen bromide in the presence of peroxide to form 1- bromopropane.
The secondary halide i.e, 2- propanol treated with metal base NaH to form sodium isopropoxide. Further treated with hydrogen bromide to form 2- Propoxypropane. This reaction follows [tex]S_{N}2[/tex] mechanism.
The overall reaction is as follows.