Answer:
m = 0.03 × 10⁴ g
Explanation:
Given data:
Specific heat capacity = 0.749 j/g.°C
Heat absorbed = 5.0 × 10⁴ J
Initial temperature = 26.0 °C
Final temperature = 275.0 °C
Mass = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2-T1
ΔT = 275.0 °C - 26.0 °C
ΔT = 249 °C
Q = m.c. ΔT
m = Q / c. ΔT
m = 5.0 × 10⁴ J / 0.749 j/g.°C × 249 °C
m = 5.0 × 10⁴ J / 186.5 j/g
m = 0.03 × 10⁴ g