Answer:
15 trees should be added to the existing orchard in order to maximize the total output of trees.
Step-by-step explanation:
Number of trees = 50
Number of apples each tree gives = 800
For each additional tree planted in the orchard, the output per tree drops by 10 apples. Let x be the number of trees added, then,
Number of apple is given by:
[tex]V(x) = (50+x)(800-10x) = -10x^2+300x + 40000 [/tex]
First, we differentiate V(x) with respect to x, to get,
[tex]\displaystyle\frac{d(V(x))}{dx} = \frac{d(-10x^2+300x + 40000)}{dx} = -20x + 300[/tex]
Equating the first derivative to zero, we get,
[tex]\displaystyle\frac{d(V(x))}{dx} = 0\\\\-20x + 300 = 0[/tex]
Solving, we get,
[tex]-20x + 300 = 0\\\\x=\displaystyle\frac{300}{20} = 15[/tex]
Again differentiation V(x), with respect to x, we get,
[tex]\displaystyle\frac{d^2(V(x))}{dx^2} = -20[/tex]
At x = 15
[tex]\displaystyle\frac{d^2(V(x))}{dx^2} < 0[/tex]
Thus, by double derivative test, the maxima occurs at x = 15 for V(x).
Thus, 15 trees should be added to the existing orchard in order to maximize the total output of trees.
Maximum output of apples =
[tex]V(15) = (50+15)(800-10(15)) = 42250[/tex]