Respuesta :
Answer:
The given equation is
[tex]\sigma^{2}=\frac{(x_{1}- \mu)^{2}+(x_{2}- \mu)^{2}+...+(x_{n}- \mu)^{2} }{N}[/tex]
What does the numerator evaluate to?
You can observe that the numerator is formed by the sum between the difference of squares. The difference is between each data and the mean of the data, this difference compares the deviation of each data regarding the mean, that's why the variance measures the degree of deviation of a data set. Additionally, the squares are made to have each difference as a positive number.
What does the denominator evaluate to?
On the other hand, the denominator represents the total number of data. With this denominator, the deviation evaluated in the numerator can be distributed to each data.
At last, the variance equals the degree of deviation of each data in average.
