Question

A certain 45 Hz AC power line radiates an electromagnetic wave having a maximum electric field strength of 12 kV/m. show answer No Attempt 50% Part (a) What is the wavelength, in meters, of this very low frequency electromagnetic wave

Answer 1

To solve this problem we must rely on the concepts related to wavelength in terms of the speed of light and frequency.

Mathematically one of the ways to express the wavelength is,

$\lambda = \frac{c}{f}$

Where,

c = Speed of light $(3*10^8m/s)$

f = Frequency

The value of the frequency given is

f = 45Hz

Therefore replacing we can find it,

$\lambda = \frac{3*10^8}{45Hz}$

$\lambda = 6.6667*10^6m$

Hence the wavelength of the very low frequency electromagnetic wave is $6.6667*10^6m$