They must sell 18 small pizzas, 12 medium pizzas and 6 large pizzas
Step-by-step explanation:
A Pizzeria sells pizza according to size:
We need to find how many of each size pizza they must sell to get $600
Assume that the number of small pizza is x, the number of medium pizza is y and the number of large pizza is z
∵ The Pizzeria sells x small pizzas, y medium pizzas and
z large pizzas
∵ The small pizzas cost $10, medium pizzas cost $15, and
large pizzas cost $40
∵ They get $600
∴ 10x + 15y + 40z = 600 ⇒ (1)
∵ They sell as many small pizzas as medium and large pizzas
combined
∴ x = y + z ⇒ (2)
∵ The number of medium pizzas sold is twice as many as large ones
∴ y = 2z ⇒ (3)
Substitute equation (3) in equation (2) to find x in terms of z only
∵ x = (2z) + z
∴ x = 3z ⇒ (4)
Substitute x in equation (1) by equation (4), and substitute y in equation (1) by equation (3)
∵ 10(3z) + 15(2z) + 40z = 600
- Simplify the left hand side
∴ 30z + 30z + 40z = 600
- Add like terms
∴ 100z = 600
- Divide both sides by 100
∴ z = 6
Substitute the value of z in equations (3) and (4) to find y and x
∵ y = 2(6)
∴ y = 12
∵ x = 3(6)
∴ x = 18
They must sell 18 small pizzas, 12 medium pizzas and 6 large pizzas
Learn more:
You can learn more about the system of equations in brainly.com/question/6075514
#LearnwithBrainly
