Question

Mark and Mike are brothers. The sum of their ages is eleven. Mike's age is ten
less than two times Mark's age. How old is each brother?
X =
Write the system:
Solution:​

Answer 1

Answer:mark is 7. Mike is 4

Step-by-step explanation:x+y=11. Y=2x-10 thus substituting for y in equation1 we have x+2x-10=11. 3x-10=11. 3x=11+10. 3x=21. X=21/3. X=7. Mike =(2×7)-10=14-10=4

Answer 2

Step-by-step explanation:

Mark's age is x

so Mike's age is

$2x - 10$

and we know that the sum of their ages is eleven so:

2x+x- 10 = 11

3x-10=11/+10

3x=21/÷3

x=7

Mark is 7 years old and

Mike is 4 years old.