Answer:
0.84 cm
Explanation:
u = Object distance = 0.35 cm
v = Image distance = -0.6 cm (near point is considered as image distance and negative due to sign convention)
f = Focal length
From lens equation
[tex]\frac{1}{f_2}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f_2}=\frac{1}{0.35}+\frac{1}{-0.6}\\\Rightarrow \frac{1}{f_2}=\frac{25}{21}\\\Rightarrow f_2=\frac{21}{25}=0.84\ cm[/tex]
Focal length of the lens is 0.84 cm