Answer:
Thus it moves 1.7 mm sideways
Solution:
As per the question:
Mass of the television, m = 25 kg
Height of the rubber pads, h = 1.0 cm = 0.01 m
Radius, R = 0.60 cm = 0.006 m
Horizontal force, F = 200 N
Shear Modulus of Rubber, G = [tex]2.6\times 10^{6}\ N/m^{2}[/tex]
Now,
To calculate the distance moved:
G = [tex]\frac{shear\ stress}{shear\ strain}[/tex]
G = [tex]\frac{\frac{Force}{Area}}{\frac{\Delta l}{L}} = \frac{Fl}{A\Delta L}[/tex]
where
[tex]\Delta L[/tex] = distance moved
Area of 4 rubber pads, A = [tex]4\times \pi R^{2}[/tex]
Now,
[tex]\Delta L = \frac{200\times 0.01}{4\times \pi 0.006^{2}\times 2.6\times 10^{6}} = 1.7\times 10^{- 3}\ m = 1.7\ mm[/tex]
