Question

A chemist prepares a solution of mercury(II) iodide HgI2 by measuring out 0.0067μmol of mercury(II) iodide into a 350.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /μmolL of the chemist's mercury(II) iodide solution. Round your answer to 2 significant digits.

Answer 1

Answer:

$\large\boxed{0.019\, \mu \text{mol/L}}$

Explanation:

$\text{Concentration } = \dfrac{\text{moles}}{\text{litres}}\\\\\text{c} = \dfrac{n}{V}$

1. Convert millilitres to litres  

$\text{V = 350. mL} \times \dfrac{\text{1 L}}{\text{1000 mL}} = \text{0.3500 L}$

2. Calculate the concentration

$c = \dfrac{0.0067\, \mu\text{mol}}{\text{0.3500 L}} = \mathbf{0.019 \,  \mu}\textbf{mol/L}\\\\\text{The concentration of mercury(II) iodide is \large\boxed{\mathbf{0.019\, \mu} \textbf{mol/L}} }.$