Question

A ring made from brass has an inner radius of 2.50000 cm and an outer radius of 3.50000 cm, giving the ring a thickness of 1.00000 cm. The thermal expansion coefficient of brass is 0.000019/°C. If the temperature of the ring is increased from 20.0°C to 90.0°C, by how much does the thickness of the ring change? _______ cm

Answer 1

Answer:0.00133 cm

Explanation:

Given

change in temperature $\Delta T=90-20=70^{\circ}C$

Thermal Expansion coefficient of brass $\alpha =0.000019 /^{\circ}C$

thickness t=1 cm

change in thickness is given by

$\Delta t=t\cdot \alpha \cdot \Delta T$

$\Delta t=1\times 0.000019\times 70$

$\Delta t=0.00133\ cm$