The equation [tex]y+3=-4(x-2)[/tex] can be transformed by doing some algebra.
If we solve the second term of the equation -4(x-2)= 8 - 4x, then we have [tex]y+3=8-4x[/tex] (this is done by distributing the multiplication into the two terms: remember that the product of -4x(-2)=+8 because the product of two negative numbers is a possitive number).
Then, by subtracting both sides 3, we have [tex]y=5-4x[/tex]. Rearranging terms in the right side, we have [tex]y=-4x+5[/tex], which is option D.
