a 3 kg piece of putty that is moving with a velocity of 10 m/s collides and sticks to an 8 kg bowling ball that was at rest. what is their velocity as they roll away together

We can solve this problem by using the principle of conservation of momentum: in fact, in absence of external forces, the total momentum of the system must be conserved before and after the collision.

Therefore we can write:

[tex]p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v[/tex]

where:

[tex]m_1 = 3 kg[/tex] is the mass of the putty

[tex]u_1 = 10 m/s[/tex] is the initial velocity of the putty (we take its direction as positive direction)

[tex]m_2 = 8 kg[/tex] is the mass of the ball

[tex]u_2 = 0 m/s[/tex] is the initial velocity of the ball (at rest)

[tex]v[/tex] is the final combined velocity of the two putty+ball

Re-arranging the equation and substituting the values, we find the final combined velocity:

[tex]v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(3)(10)+0}{3+8}=2.7 m/s[/tex]

And the positive sign indicates their final direction is the same as the initial direction of the putty.

Learn more about momentum here:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly