Question

Suppose we consider the system of the three capacitors as a single "equivalent" capacitor. Given the charges of the three individual capacitors calculated in the previous part, find the total charge Qtot for this equivalent capacitor.

Answer 1

Answer:

Qtot = 6C * deltaV

Explanation:

you can find the total capacitance from adding 1C+2C+3C=6C. and the total voltage is 1V. Capacitance = charge/voltage--> C = Q / V--> 6C = Q / deltaV. this makes Qtot = 6C* deltaV

Answer 2

The Total charge for the equivalent circuit is =  $Q_{tot}$ = 6c * ΔV

  Although your question is incomplete I found the missing part online and used it to resolve the question

Given data :

Total capacitance ( C ) = 6C ( 1 + 2 + 3 )

voltage = 1 V

Three capacitors having values of ; 1 C, 2 C,  3 C

Determine the total charge ( Qtot )

Applying the formula ; Q = CV ----  ( 1 )

 where; Q =  charge

              C = capacitance

              change in V = ΔV

∴ $Q_{tot}$ = 6c * ΔV

Hence the total charge Qtot for the equivalent capacitor =  6c * ΔV

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