Question

Elizabeth brought a box of donuts to share. There are​ two-dozen (24) donuts in the​ box, all identical in​ size, shape, and color. Three are​ jelly-filled, four are​ lemon-filled, and seventeen are​ custard-filled. You randomly select one​ donut, eat​ it, and select another donut.
Find the probability of selecting a lemon​-filled donut followed by a custard-filled donut.

Answer 1

Answer:

P = 68/552 = 0.123 or 12.3%

Step-by-step explanation:

First, let's calculate the probability of getting a lemon donut. We have only 4 lemon donut among 24 donuts, so probability is:

P(A) = 4/24

Next, as we already ate the lemon donut, we only have 23 donuts now, and among these 23, 17 are custard filled, so probability of choosing one of those is:

P(B) = 17/23

But we want to know the probability that the custard filled donut is choosen after you eat the lemon one so:

P(B|A) = P(A) * P(B)

Replacing:

P(B|A) = 4/24 * 17/23

P(B|A) = 68/552 = 0.123 or 12.3%