Question

If the engine in a 1200 kg car could produce 10,000 N to accelerate from 0 to 27
m/s, how much time would that take?

Answer 1

Answer:

The time taken by engine of the car to accelerate is 3.24 seconds

Step-by-step explanation:

Given as :

The mass of the car = 1200 kg

The Force applied by engine to accelerate = 10, 000 N

The change in velocity = $v_2$ -  $v_1$ = 27 m/s

Let The time taken by engine = t sec

And Let The acceleration = a  m/s²

Now,

∵ Force is define as the product of mass and acceleration

I.e F = mass × acceleration

or, F = 1200 × a

or, 10,000 =  1200 × a

∴ a = $\frac{10,000}{1200}$   m/s²

I.e a = 8.33 m/s²

Now , Again

∵ Acceleration is define as the rate of change of velocity

I.e a = $\dfrac{v_2-v_1}{t}$

or, a =  $\dfrac{27-0}{t}$

Or, t =  $\dfrac{27}{a}$

I.e t = $\dfrac{27}{8.33}$

∴ t = 3.24 sec

So, The time taken = 3.24 seconds

Hence The time taken by engine of the car to accelerate is 3.24 seconds . Answer