Question

The melting of an ice sculpture of BEVO at room temperature requires 10 kJ of energy. Calculate the change in entropy of the surroundings. Please report your answer one point past the decimal with the unit J/K.

Answer 1

Answer:

The change in entropy of surrounding = -33.5 J/k

Explanation:

Heat gained by the ice = 10 kJ = 10000 J

Heat lost by surrounding = -(Heat gained by ice)

Hence,

Heat lost by surrounding = -(10000 J)

The given room temperature = $25^{o}C$ = 273 + 25 = 298 K

$Change\,\,in\,\,entropy\,\,surrounding =\frac{Heat\,\,lost\,\,by\,\,surrounding}{Room\,\,temperature}$$= \frac{-10000}{298}= 33.5\,J/k$

Therefore, The change in entropy of surrounding = -33.5 J/k