You have 31 nickels and 44 dimes.
Step-by-step explanation:
Total coins = 75
Worth of coins = $5.95 = 5.95*100 = 595 cents
1 nickel = 5 cents
1 dime = 10 cents
Let,
Number of nickels = x
Number of dimes = y
According to given statement;
x+y=75 Eqn 1
5x+10y=595 Eqn 2
Multiplying Eqn 1 by 5
[tex]5(x+y=75)\\5x+5y=375\ \ \ Eqn\ 3\\[/tex]
Subtracting Eqn 3 from Eqn 2
[tex](5x+10y)-(5x+5y)=595-375\\5x+10y-5x-5y=220\\5y=220[/tex]
Dividing both sides by 5
[tex]\frac{5y}{5}=\frac{220}{5}\\y=44[/tex]
Putting y=44 in Eqn 1
[tex]x+44=75\\x=75-44\\x=31[/tex]
You have 31 nickels and 44 dimes.
Keywords: linear equations, subtraction
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