Respuesta :
Answer: The nitrogen atom is getting reduced.
Explanation:
Oxidation reaction is defined as the reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.
[tex]X\rightarrow X^{n+}+ne^-[/tex]
Reduction reaction is defined as the reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.
[tex]X^{n+}+ne^-\rightarrow X[/tex]
The given chemical equation follows:
[tex]Fe_2S_3+12HNO_3\rightarrow 2Fe(NO_3)_3+3S+6NO_2+6H_2O[/tex]
On reactant side:
Oxidation state of iron atom = +3
Oxidation state of nitrogen atom = +5
Oxidation state of sulfur atom = -2
On product side:
Oxidation state of iron atom = +3
Oxidation state of sulfur atom = 0
Oxidation state of nitrogen atom in [tex]NO_2[/tex] = +4
Oxidation state of nitrogen atom in [tex]Fe(NO_3)_3[/tex] = +5
As, the oxidation state of nitrogen atom in [tex]NO_2[/tex] is decreasing from +5 to +4. So, it is getting reduced.
And, oxidation state of sulfur atom is increasing from -2 to 0. So, it is getting oxidized.
Hence, the nitrogen atom is getting reduced.
The element that gets reduced in the chemical reaction is nitrogen.
What is reduction?
Reduction in chemistry means when an atom accepts electrons to become more negatively charged.
According to this question, the following chemical reaction is given:
Fe2S3 + 12HNO3 → 2Fe(NO3)3 + 3S + 6NO2 + 6H2O
On reactant side:
- Oxidation state of iron atom = +3
- Oxidation state of nitrogen atom = +5
- Oxidation state of sulfur atom = -2
On product side:
- Oxidation state of iron atom = +3
- Oxidation state of sulfur atom = 0
- Oxidation state of nitrogen atom in = +4
As indicated above, the oxidation number of nitrogen reduces from +5 to +4, hence, it is the element that gets reduced.
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