Question

A rock of mass m = 0.0450 kg is attached to one end of a string and is whirled around in a horizontal circle. If the radius of the circle is 0.580 m and the angular speed is 2.34 rad/s. What is the tension in the string?

Answer 1

Answer:

Tension, T = 0.1429 N

Explanation:

Given that,

Mass of the rock, m = 0.0450 kg

Radius of the circle, r = 0.580 m

Angular speed, $\omega=2.34\ rad/s$

The tension in the string is balanced by the centripetal force acting on it. It is given by :

$T=\dfrac{mv^2}{r}$

Since, $v=r\omega$

$T=\dfrac{m(r\omega)^2}{r}$

$T=\dfrac{0.0450\times (0.580\times 2.34)^2}{0.580}$

T = 0.1429 N

So, the tension in the string is 0.1429 N. Hence, this is the required solution.