Answer:
a.$7,096
Step-by-step explanation:
[this is the formula used when certain amount is added at regular intervals and if the interest is COMPOUNDED]
(here,
s=deposit added at the end of each quarter= $500
n= number of times interest is compounded per unit 't'=4
t=total time = 3 years
r=interest rate ( expressed in decimal or fraction not in %) = 12/100 = 0.12 )
A [tex]=500(\frac{(1.03) ^{12}-1 }{0.03} )\\\\=500(\frac{1.42576-1}{0.03} )\\\\=500(\frac{0.42576}{0.03}) \\=$7,096[/tex]
( [1.03]^12= 1.42576 ( approximately) { use calculator for exact values})