Answer:
option A
Explanation:
given,
velocity to hit home plate = 110 Km/h
a) When the baseball is hit straight back
Assuming the momentum before hitting be P and after hitting the bal is also equal to P.
change in momentum = P - (-P) = 2P
b) When the catcher catches the ball the change in momentum is equal to zero.
c) when the ball is popped up the change in momentum
p_x = P and P_y = P
resultant momentum = [tex]\sqrt{P^2+ P^2} = \sqrt{2}\ P[/tex]
the maximum change in momentum will be in case A
The correct answer is option A