Question

Identify the final concentrations of each species following the addition of 1.0 M KOH to a 2.0 M HF solution. HF ( aq ) + KOH ( aq ) ⟶ KF ( aq ) + H 2 O ( l ) initial 2.0 M 1.0 M 0 M change final ? ? ?

Answer 1

Answer : The final concentration of KOH, HF and KF are 0 M, 1.0 M and 1.0 M respectively.

Explanation :

The given chemical reaction is:

                      $HF(aq)+KOH(aq)\rightarrow KF(aq)+H_2O(l)$

Initial conc.   2.0 M       1.0 M            0 M

Final conc.    1.0 M         0 M             1.0 M

When 1.0 M of KOH react with 2.0 M HF  then 1.0 M KOH will react with 1.0 M HF to form 1.0 M KF and 1.0 M HF remain unreacted.

So, the final solution contains 1.0 M HF and 1.0 M KF that means the solution contains equal amount of weak acid and salt.

Therefore, the final concentration of KOH, HF and KF are 0 M, 1.0 M and 1.0 M respectively.

Answer 2

The final concentration of KOH, HF and KF are 0 M, 1.0 M and 1.0 M respectively.

Chemical reaction:

HF ( aq ) + KOH ( aq ) ⟶ KF ( aq ) + H₂O ( l )

Initial conc.   2.0 M       1.0 M            0 M

Final conc.    1.0 M         0 M             1.0 M

When 1.0 M of KOH react with 2.0 M HF then 1.0 M KOH will react with 1.0 M HF to form 1.0 M KF and 1.0 M HF remain unreacted. So, the final solution contains 1.0 M HF and 1.0 M KF that means the solution contains equal amount of weak acid and salt.

Therefore, the final concentration of KOH, HF and KF are 0 M, 1.0 M and 1.0 M respectively.

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