Question

Find the sum of the first 10 terms of the following geometric sequences:
{3, 6, 12, 24, 48...)

Answer 1

Answer:

3069

Step-by-step explanation:

q=6/3=2

s10=3(2^10-1)÷(2-1)=3×(1024-1)=

3069

because sn=a1(q^n-1)/(q-1)

Answer 2

Answer:

3069

Step-by-step explanation:

q=6/3=2

s10=3(2^10-1)÷(2-1)=3×(1024-1)=

3069