Answer: Yes, this suggest that the actual percentage of type A donations differs from 40%, the percentage of the population having type A blood.
Step-by-step explanation:
Since we have given n = 157
x = 86
So, [tex]\hat{p}=\dfrac{x}{n}=\dfrac{86}{157}=0.55[/tex]
and we have p = 0.4
So, hypothesis would be
[tex]H_0:p=\hat{p}\\\\H_a:p\neq \hat{p}[/tex]
Since there is 1% level of significance.
So, test statistic value would be
[tex]z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.55-0.40}{\sqrt{\dfrac{0.4\times 0.6}{157}}}\\\\z=\dfrac{0.15}{0.039}\\\\z=3.846[/tex]
and the critical value at 1% level of significance , z = 2.58
Since 2.58<3.846.
So, we reject the null hypothesis.
Hence, Yes, this suggest that the actual percentage of type A donations differs from 40%, the percentage of the population having type A blood.