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Answer:
The number of small and large boxes purchased are:
- 2 small boxes.
- 6 large boxes.
Step-by-step explanation:
To solve the unknowns, two equations must be established with the information provided:
- 150X + 400Y = 2700 (the price of the boxes and the final number of nails, where X is the small boxes and Y the large boxes)
- Y = 3X (Large boxes are triple the small ones)
Then equation 2 is replaced in equation one and variable X is cleared:
- 150X + 400 (3X) = 2700
- 150X + 1200X = 2700
- 1350X = 2700
- X = 2700/1350
- X = 2
Finally, the value of X is replaced in equation 2 to find the number of large boxes:
- Y = 3X
- Y = 3 (2)
- Y = 6
2 small boxes and 6 large boxes
Let x represent the number of small boxes and let y represent the number of big boxes.
Since the contractor bought 3 times as many large boxes as small boxes, hence:
y = 3x
-3x + y = 0 (1)
Also, the each small box has 150 nails and each large box has 400 nails. They were 2700 nails altogether, hence:
150x + 400y = 2700 (2)
Solve equation 1 and 2 simultaneously. First multiply equation 1 by 50 and add to (2) gives:
450y = 2700
y = 6
6 = 3x
x = 2
There were 2 small boxes and 6 large boxes purchased
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