For this case we have that by definition, the equation of a line in the standard form is given by:
[tex]ax + by = c[/tex]
According to the statement we have the following equation of the line:
[tex]y + 1 = \frac {2} {5} (x + 3)[/tex]
We manipulate algebraically to write in the standard form. To do this we follow the steps below:
We apply distributive property on the right side of the equation:[tex]y + 1 = \frac {2} {5} x + \frac {6} {5}[/tex]
We subtract [tex]\frac {6} {5}[/tex] on both sides of the equation:
[tex]y + 1- \frac {6} {5} = \frac {2} {5} x\\y- \frac {1} {5} = \frac {2} {5} x[/tex]
We multiply by 5 on both sides of the equation:
[tex]5y-1 = 2x[/tex]
We subtract 5y on both sides of the equation:
[tex]2x-5y = -1[/tex]
Finally, the equation in its standard form is:
[tex]2x-5y = -1[/tex]
Answer:
[tex]2x-5y = -1[/tex]