Answer
given,
Power output of loud train = 100 W
Distance of intensity level from train= 100 m
I₀ = 10⁻¹² W/m²
Intensity of sound = ?
we know,
[tex]I = \dfrac{P}{Area}[/tex]
[tex]I = \dfrac{P}{4\pi r^2}[/tex]
[tex]I = \dfrac{100}{4\pi 100^2}[/tex]
[tex]I =7.957\times 10^{-4}\ W/m^2[/tex]
Intensity level
= [tex]10 log(\dfrac{I}{I_0})[/tex]
= [tex]10 log(\dfrac{7.975\times 10^{-4}}{10^{-12}})[/tex]
= [tex]10 \times 8.900[/tex]
= 89 dB