Question

an unbalanced force of 2 N ask on a 3 kg object for six seconds the magnitude of the objects change in velocity is
yes 1)18m/s 2)2m/s 3)36m/s 4)4.0m/s

Answer 1

The change in velocity is 4) 4.0 m/s

Explanation:

First of all, we can find the acceleration of the object, by applying Newton's second law:

$F=ma$

where

F = 2 N is the net force on the object

m = 3 kg is the mass of the object

a is the acceleration

Solving for a,

$a=\frac{F}{m}=\frac{2}{3}=0.67 m/s^2$

The motion of the object is a uniformly accelerated motion, so we can use the suvat equation:

$v=u+at$

where

u is the initial velocity

v is the final velocity

$a=0.67 m/s^2$ is the acceleration

t = 6 s is the time elapsed

Therefore, the change in velocity is

$v-u = at=(0.67)(6)=4.0 m/s$

Learn more about Newton's second law and acceleration:

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