Question

a line with a slope of 5/3 passes through the point (10, -5). what is its equation in point slope​

Answer 1

The equation of line in point-slope form with slope 5/3 passing through the point (10-5) is:

$y+5 = \frac{5}{3}(x-10)$

Step-by-step explanation:

Given

Slope = m = 5/3

Point = (x1,y1) = (10, -5)

Point-slope form is:

$y-y_1 = m(x-x_1)$

As the slope and point is already given, we only have to put the values in the equation to get the equation of required line:

$y-(-5) = \frac{5}{3}(x-10)\\y+5 = \frac{5}{3}(x-10)$

Hence,

The equation of line in point-slope form with slope 5/3 passing through the point (10-5) is:

$y+5 = \frac{5}{3}(x-10)$

Keywords: equation of line, point-slope form

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