Question

it’s literal equations and i really need help

Answer 1

Answer:

Part 1) $x=\frac{g}{c}$

Part 2) $a=\frac{1}{3b}$

Part 3) $a=\frac{n+p}{m}$

Part 4) $x=g-y+c$

Part 5) $x=\frac{z}{m-1}$

Part 6) $a=\frac{g+b}{c}$

Part 7) $b=\frac{A}{h}$

Part 8) $W=\frac{P}{2}-L$

Part 9) $d=2Q-c$

Part 10) $a=\frac{Q}{3+5c}$

Part 11) $N=\frac{A)}{P-IR}$

Part 12) $b=P-a-c$

Step-by-step explanation:      

Part 1) we have

$g=xc$

solve for x

That means---> Isolate the variable x

Divide by c both sides

$\frac{g}{c}=\frac{xc}{c}$

simplify

$x=\frac{g}{c}$

Part 2) we have

$12ab=4$

solve for a

That means---> Isolate the variable a

Divide by 12b both sides

$\frac{12ab}{12b}=\frac{4}{12b}$

simplify

$a=\frac{1}{3b}$

Part 3) we have

$am=n+p$

solve for a

That means---> Isolate the variable a

Divide by m both sides

$\frac{am}{m}=\frac{n+p}{m}$

simplify

$a=\frac{n+p}{m}$

Part 4) we have

$g=x-c+y$

solve for x

That means---> Isolate the variable x

Subtract y both sides

$g-y=x-c+y-y$

$g-y=x-c$

Adds c both sides

$g-y+c=x-c+c$

$g-y+c=x$

rewrite

$x=g-y+c$

Part 5) we have

$xm=x+z$

solve for x

That means---> Isolate the variable x

Subtract x both sides

$xm-x=x+z-x$

$xm-x=z$

Factor x left side

$x(m-1)=z$

Divide by (m-1) both sides

$\frac{x(m-1)}{m-1}=\frac{z}{m-1}$

$x=\frac{z}{m-1}$

Part 6) we have

$g=ca-b$

solve for a

That means---> Isolate the variable a

Adds b both sides

$g+b=ca-b+b$

$g+b=ca$

Divide by c both sides

$\frac{g+b}{c}=\frac{ca}{c}$

$a=\frac{g+b}{c}$

Part 7) we have

$A=bh$

solve for b

That means---> Isolate the variable b

Divide by h both sides

$\frac{A}{h}=\frac{bh}{h}$

simplify

$b=\frac{A}{h}$

Part 8) we have

$P=2L+2W$

solve for W

That means---> Isolate the variable W

Subtract 2L both sides

$P-2L=2L+2W-2L$

simplify

$P-2L=2W$

Divide by 2 both sides

$\frac{P-2L}{2}=\frac{2W}{2}$

simplify

$W=\frac{P-2L}{2}$

$W=\frac{P}{2}-L$

Part 9) we have

$Q=\frac{c+d}{2}$

solve for d

That means---> Isolate the variable d

Multiply by 2  both sides

$2Q=(2)\frac{c+d}{2}$

simplify

$2Q=c+d$

subtract c both sides

$2Q-c=c+d-c$

$2Q-c=d$

rewrite

$d=2Q-c$

Part 10) we have

$Q=3a+5ac$

solve for a

That means---> Isolate the variable a

Factor the variable a in the right side

$Q=a(3+5c)$

Divide by (3+5c) both sides

$\frac{Q}{3+5c}=\frac{a(3+5c)}{3+5c}$

simplify

$a=\frac{Q}{3+5c}$

Part 11) we have

$I=\frac{PN}{RN+A}$

solve for N

That means---> Isolate the variable N

Multiply in cross

$I(RN+A)=PN$

Apply distributive property left side

$IRN+AI=PN$

subtract PN both sides

$IRN+AI-PN=PN-PN$

$IRN+AI-PN=0$

subtract AI both sides

$IRN+AI-PN-AI=-AI$

$IRN-PN=-AI$

Factor N left side

$N(IR-P)=-AI$

Divide by (IR-P) both sides

$\frac{N(IR-P)}{IR-P}=-\frac{A}{IR-P}$

simplify

$N=-\frac{A}{IR-P}$

$N=\frac{A}{P-IR}$

Part 12) we have

$P=a+b+c$

solve for b

That means---> Isolate the variable b

subtract (a+c) both sides

$P-(a+c)=a+b+c-(a+c)$

simplify

$P-(a+c)=b$

rewrite

$b=P-a-c$