Question

Which exponential function has an initial value of 2? f(x) = 2(3x) On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases into quadrant 1. It crosses the y-axis at (0, 0.5) and goes through (2, 2). f(x) = 3(2x) A 2-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f (x) with entries one-eighth, one-fourth, one-half, 1, 2.

Answer 1

Answer:

The correct answer is A. f(x)= 2(3^x)

Step-by-step explanation:

Answer 2

The exponential function y = 2(3)ˣ, has an initial value of 2

Exponential function

An exponential function is in the form:

y = abˣ

where y, x are variables, a is the initial value of y and b is the multiplicative rate of change

Given the exponential function y = 2(3)ˣ, has an initial value of 2

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