Answer:
The cheerleader does a total work of 8,532 J (8,541 J without any intermediate rounding)
Explanation:
Hi there!
The equation of work is the following:
W = F · d
Where:
W = work.
F = applied force.
d = distance.
The cheerleader´s partner is on the ground due to the force of gravity acting on her, also known as weight. To lift the partner at a constant velocity, the cheerleader has to suppress this force applying on the partner a force that is equal to the partner´s weight but in opposite direction.
The weight of the partner is calculated as follows:
Weight = m · g
Where m is the mass of the partner and g is the acceleration due to gravity.
Let´s calculate the weight of the partner:
Weight = 43.8 kg · 9.8 m/s²
Weight = 429 N
]Then, the work done in one lift by the cheerleader is the following:
W = F · d
W = 429 N · 0.737 = 316 J
If the cheerleader does 27 lifts, the work done will be (316 J · 27) 8,532 J
