Required number is [tex]\frac{-13}{5}[/tex] and required expression is n – 10 = 6n + 3
Given that
Ten less than a number is three more than six times the number.
Number is represented by variable "n"
Need to determine equation and the number.
Ten less than number means subtracting 10 from the number
As number is n so ten less than number = n – 10 ------(1)
Six times the number = number multiplied by 6 = 6n
So three more than Six times the number = 6n + 3 --------(2)
As ten less than number is equal to 3 more than six times the number
=> n – 10 = 6n + 3
Solving the above expression for n we get
-10-3 = 6n – n
=> 5n = -13
[tex]\Rightarrow \mathrm{n}=-\frac{13}{5}[/tex]
Hence required number is [tex]-\frac{13}{5}[/tex] and required expression is n – 10 = 6n + 3