Answer:
3/4
Explanation:
The first parent with the "AABBCc" genotype would express the dominant trait for all the three loci since the mentioned loci exhibit simple dominance for each trait and independent assortment. Therefore, the desired progeny should also exhibit the dominant trait for all three loci.
Parents= AABBCc × AabbCc
AA x Aa= 1/2 AA (dominant): 1/2 Aa (dominant) = 100% dominant progeny
BB x bb = Bb (dominant) = 100% dominant progeny
Cc x Cc = 1/4 CC (dominant): 1/2 Cc (dominant): 1/4 cc (recessive) = 3/4 dominant : 1/4 recessive progeny
Therefore, the proportion of the progeny showing the dominant trait for all the three loci= 1 x 1 x 3/4 = 3/4
