Two long, straight wires are parallel and 16 cm apart. One carries a current of 2.9 A, the other a current of 5.7 A. (a) If the two currents flow in opposite directions, what is the magnitude (in N/m) and direction of the force per unit length of one wire on the other?

Respuesta :

Explanation:

Given that,

Distance between two long wires, d = 16 cm = 0.16 m

Current in one wire, [tex]I_1=2.9\ A[/tex]

Current in wire 2, [tex]I_2=5.7\ A[/tex]    

The magnetic force per unit length of one wire on the other is given by the following expression as :

[tex]\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi d}[/tex]

[tex]\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 2.9\times 5.7}{2\pi \times 0.16}[/tex]

[tex]\dfrac{F}{l}=2.06\times 10^{-5}\ N/m[/tex]

The current is flowing in opposite direction, the magnetic force acting on it is repulsive. Hence, this is the required solution.