Question

Consider the titration of 30.0 mL of 0.050 M NH3 with 0.025 M HCl.

Calculate the after the following volumes of titrant have been added.

a)0 mL

b)20.0mL

c)59.2mL

d)60.0mL

e)71.3mL

f)73.3mL

Answer 1

Answer:

60.0mL

Explanation:

For the process of titration , the formula we use is -

M₁V₁ = M₂V₂

Where ,

M₁ = initial concentration

V₁ = initial volume

M₂ = final concentration

V₂ = final volume .

Hence , from the question ,

The given data is ,

M₁ = 0.050 M

V₁ = 30.0mL

M₂ = 0.025 M

V₂ = ?

Now, to determine the unknown quantity , the formula can be applied ,

Hence ,

M₁V₁ = M₂V₂

Putting the respective values ,

0.050 M * 30.0mL = 0.025 M * ?

solving the above equation ,

V₂ = ? = 60.0mL