Question

find the equation of a line that is perpendicular to the given line and passes through the given point. enter your answer in slope intercept form y=mx+b with the values of m and b given as decimals, rounded to the nearest hundredth. y =10x ; (8,-2)

Answer 1

Answer:

m= -0.1

b= -1.2

Step-by-step explanation:

The equation of the given line is

y=10x, slope of the given line is 10.

As the line is perpendicular to this line, the slope  is $-\frac{1}{10}$

m= -0.1

( product of slope of two perpendicular lines is -1)

thus the equation is

$y = (-\frac{1}{10})x + b$

$y = (-0.1)x + b$

now to find the value of b, input the point coordinates (8, -2) in the above equation.

$-2 = (-0.1)(8) + b$

$b = -2 + (0.8)$

b = -1.2