Respuesta :
Explanation:
The bond order is defined as number of electron pairs present in a bond of the two atoms.
The formula of bond order is given by:
= [tex]\frac{1}{2}\times (\text{Number of bonding electrons}-\text{Number of anti-bonding electrons})[/tex]
1) [tex](\sigma 1 s )^2 ( \sigma 1 s*)^2 (\sigma 2s )^2 ( \sigma 2 s*)^2 ( \sigma 2 p )^2 ( \pi2 p )^4 (\pi 2 p *)^2 [/tex]
Number of bonding electrons = 10
Number of anti-bonding electrons = 6
The bond order : [tex]\frac{1}{2}\times (10-6)=2[/tex]
2) [tex]( \sigma 1 s )^2 ( \sigma 1 s * )^2 ( \sigma 2 s )^2[/tex]
Number of bonding electrons = 4
Number of anti-bonding electrons = 2
The bond order : [tex]\frac{1}{2}\times (4-2)=1[/tex]
Answer:
Bond order is defined as the difference between bonding and anti-bonding pairs of the atom or molecule. Bond order determines the bond length, strength, and stability of the chemical compound.
Explanation:
Bond order is the measurement of electrons present in the binding and anti-bonding orbitals of a n atom. It is calculated by the difference of bonding and anti-boding orbitals.
Bond Order:
[tex]&= \frac{1}{2} \times ( \text {Number of bonding electrons} - \text {Number of anti-bonding electrons})[/tex]
1) Bond Order of [tex]( \sigma 1)^{2} ( \sigma 1 s*)^{2} ( \sigma 2s)^{2} ( \sigma 2s*)^{2} ( \sigma 2p)^{2} ( \sigma 2p*)^{2}( \sigma \pi2p)^{4} ( \sigma 2p*)^{2} \\[/tex] will be:
Number of bonding electrons = 10
Number of anti-bonding electrons = 6
Therefore, the bond order = [tex]&= \frac{1}{2} \times ( \text {10} - \text {6}) &=2[/tex][tex]&= \frac{1}{2} \times ( \text {10} - \text {6}) =2[/tex]
Similary,
2) Bond order of [tex]( \sigma 1)^{2} ( \sigma 1 s*)^{2} ( \sigma 2s)^{2}[/tex] will be:
Number of bonding electrons = 4
Number of anti-bonding electrons = 2
Bond order = [tex]&= \frac{1}{2} \times ( \text {4} - \text {2}) &=1[/tex]
For Further Reference:
https://brainly.com/question/13421940?referrer=searchResults
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