Question

A student sees her physical science professor approaching on the sidewalk that runs by her dorm. She gets a water balloon and waits. When the professor is 2 s from being directly under her window 11 m above the idewalk, she drops the balloon. You finish the story. (Assume g # 10 m/s*)

Answer 1

Answer:Misses the Target

Explanation:

Given

Distance between window and Professor is h=11 m

she dropped the balloon 2 sec earlier

time taken by balloon to cover the 11  m

using

$h=ut+\frac{at^2}{2}$

where h=height

u=initial velocity

t=time

a=acceleration

$11=0+\frac{9.8t^2}{2}$

$t=\sqrt{\frac{2\times 11}{10}}$

$t=\sqrt{2.2}$

$t=1.483 s$

Therefore she misses the Professor by 0.51 s