Answer: Option (A) is the correct answer.
Explanation:
It is known that relation between pressure, density, height, and gravity is as follows.
P = [tex]\rho \times g \times h[/tex]
As it is given that pressure of both mercury and water column are equal. Therefore,
[tex]\rho_{Hg} \times g \times h_{Hg} =\rho_{H_{2}O} \times g \times h_{H_{2}O}[/tex]
Cancelling the common terms in the formula. Now, putting the given values into the above formula as follows.
[tex]\rho_{Hg} \times g \times h_{Hg} =\rho_{H_{2}O} \times g \times h_{H_{2}O}[/tex]
[tex]13.6 g/cm^{3} \times 256 mm = 1 \times h_{H_{2}O}[/tex]
3481.6 mm = [tex]h_{H_{2}O}[/tex]
As 1 mm = 0.1 cm
[tex]3481.6 mm \times \frac{0.1 cm}{1 mm}[/tex]
= 348.1 cm
or, = 348 cm (approx)
thus, we can conclude that height of the given column is 348 cm.