Respuesta :
Answer:
Part-A:
Anode is Nickel and Cathode is copper.
Part -B:
[tex]E^{0}_{cell}[/tex] of the reaction is 0.567V.
Explanation:
Nickel-Copper cell electrodes are "Ni" and "Cu" rod.
Nickel electrode is dipped in [tex]Ni^{+2}[/tex] solution.
Copper electrode dipped in [tex]Cu^{+2}[/tex] solution.
Part -A:
Anode:
At anode oxidation takes place
[tex]Ni(s) \rightarrow Ni^{+2}(aq)+2e^{-}[/tex]
Hence, anode is Nickel.
Cathode:
At cathode reduction takes place.
[tex]Cu^{+2}+2e^{-} \rightarrow Cu(s)[/tex]
Hence, Cathode is copper.
Part-B:
[tex]E^{0}_{cell}=E^{0}_{cathode}-E^{0}_{anode}[/tex]
[tex]=0.337-(-0.230)=0.567V[/tex]
Hence, [tex]E^{0}_{cell}[/tex] of the reaction is 0.567V.
Anodes and cathodes are the electrodes where oxidation and reduction take place.
What are the electrodes in galvanic cell?
Electrochemical cells have two electrodes which is called anode and cathode. The anode is the electrode where oxidation occurs while the other hand, cathode is the electrode where reduction takes place so we can conclude that anodes and cathodes are the electrodes where oxidation and reduction take place.
Learn more about electrodes here: https://brainly.com/question/18251415